[CS4423]: WK09-2 lecture materials & notes
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year4/semester2/CS4423/assignments/assignment2/CS4423-HW2-1.pdf
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year4/semester2/CS4423/assignments/assignment2/CS4423-HW2-1.pdf
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year4/semester2/CS4423/materials/CS4423-W09-Part-2.pdf
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year4/semester2/CS4423/materials/CS4423-W09-Part-2.pdf
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@ -1078,7 +1078,19 @@ Also, the \textbf{average degree} of a randomly chosen node is
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\langle k \rangle = \sum^{n-1}_{k=0} kp_k = p(n-1)
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\end{align*}
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(with standard deviation $\sigma_k = \sqrt{p(1-p)(n-1))}.
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(with standard deviation $\sigma_k = \sqrt{p(1-p)(n-1))}$.
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\\\\
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In general, it is not so easy to compute
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\[
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\binom(n-1)(k) p^k (1-p)^{n-1-k}
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\]
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However, in the limit $n \to \infty$ with $\langle k \rangle k = p(n-1)$ kept constant, the binomial distribution $\text{bin}(n-1,p,k)$ is well-approximated by the \textbf{Poisson distribution}:
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\[
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p_k = e^{-\lambda} \frac{\lambda^k}{k!} = \text{Pois}(\lambda, k)
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\]
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where $\lambda = p(n-1)$.
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